From ...
From: Erik Naggum <erik@naggum.net>
Subject: Re: How to display source of interpreted function
Date: 2000/11/10
Message-ID: <3182847091422316@naggum.net>#1/1
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* John Clonts <jclonts@mastnet.net>
| Is there any function I can call to display the source, such as

  This is pretty simple if you know what to expect, since you can't
  quite back the source, which exist before macroexpansion of defun.
  defun store a function definition in the function slot of the symbol,
  possibly after transforming the function body.
        
(9322) cl-user
(defun john (x) (* x x))
=> john
(9323) cl-user
(function-lambda-expression #'john)
=> (lambda (x) (block john (* x x)))
=> nil
=> john

  The preferred way to display the source is to write your Common Lisp
  code in the editor and compile (or evaluate) it from there, or compile
  and/or load the file itself.  The Emacs/Lisp interface from Franz Inc
  or ILISP from other sources or even Emacs' built-in inferior lisp mode
  may all help in connecting with the running Lisp system to do this.

#:Erik
-- 
 Al-Gore-ism: a procedure for solving an electoral problem in a finite
 number of steps that frequently involves repetition of an operation.
 See also algorithm.